b-2=(18-3b)^1/2

Solution for b-2=(18-3b)^1/2 equation:

b-2=(18-3b)^1/2

We move all terms to the left:

b-2-((18-3b)^1/2)=0

We add all the numbers together, and all the variables

b-((-3b+18)^1/2)-2=0

We multiply all the terms by the denominator


b*2)-((-3b+18)^1-2*2)=0

We add all the numbers together, and all the variables

b*2)-((-3b+18)^1=0

Wy multiply elements

2b^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$b=\frac{-b}{2a}=\frac{0}{4}=0$